![SOLVED: Question The equations of normal plane and osculating plane of the curve ,6)=2ti 'j kat (0.0.2):=0(0) are Normal plane 2 v =0. osculating plane + 2) =0 Normal plane 2 4 = SOLVED: Question The equations of normal plane and osculating plane of the curve ,6)=2ti 'j kat (0.0.2):=0(0) are Normal plane 2 v =0. osculating plane + 2) =0 Normal plane 2 4 =](https://cdn.numerade.com/ask_images/4977d5b56965494595ca892841ea35a7.jpg)
SOLVED: Question The equations of normal plane and osculating plane of the curve ,6)=2ti 'j kat (0.0.2):=0(0) are Normal plane 2 v =0. osculating plane + 2) =0 Normal plane 2 4 =
![SOLVED: EXAMPLE 7 Find the equations of the normal plane and osculating plane of the helix r(t) = 5 cos(t) + 5 sin(t) j + tk the point P(O, 5, 1/2) SOLUTION SOLVED: EXAMPLE 7 Find the equations of the normal plane and osculating plane of the helix r(t) = 5 cos(t) + 5 sin(t) j + tk the point P(O, 5, 1/2) SOLUTION](https://cdn.numerade.com/ask_images/94b15b9cb34442f8960ee9ebe3662048.jpg)
SOLVED: EXAMPLE 7 Find the equations of the normal plane and osculating plane of the helix r(t) = 5 cos(t) + 5 sin(t) j + tk the point P(O, 5, 1/2) SOLUTION
![Exam 1 Review - Lecture notes Nanes - Ex Let Flt 3 2t t Find an equation of the plane normal toIct - StuDocu Exam 1 Review - Lecture notes Nanes - Ex Let Flt 3 2t t Find an equation of the plane normal toIct - StuDocu](https://d20ohkaloyme4g.cloudfront.net/img/document_thumbnails/5d325c87d53c2141468de83e4df716c9/thumb_1200_1570.png)
Exam 1 Review - Lecture notes Nanes - Ex Let Flt 3 2t t Find an equation of the plane normal toIct - StuDocu
![SOLVED: Consider the following_ x = sin(6t) , Y = cos(6t) , 2 = 24t; (0, 1, 4t) Find the equation of the normal plane of the curve at the given point: SOLVED: Consider the following_ x = sin(6t) , Y = cos(6t) , 2 = 24t; (0, 1, 4t) Find the equation of the normal plane of the curve at the given point:](https://cdn.numerade.com/ask_images/d734c2ad1adc4327b8440218b7591c6d.jpg)
SOLVED: Consider the following_ x = sin(6t) , Y = cos(6t) , 2 = 24t; (0, 1, 4t) Find the equation of the normal plane of the curve at the given point:
![SOLVED: If the fuction f(t) is of the form given below t < 0 e-1/t2 t > 0 Consider the curve x(t) = (t,f(t), f(-t)) . Then which of the following is SOLVED: If the fuction f(t) is of the form given below t < 0 e-1/t2 t > 0 Consider the curve x(t) = (t,f(t), f(-t)) . Then which of the following is](https://cdn.numerade.com/ask_images/30f7547a01514f1084ffe9b3d06d1e0c.jpg)
SOLVED: If the fuction f(t) is of the form given below t < 0 e-1/t2 t > 0 Consider the curve x(t) = (t,f(t), f(-t)) . Then which of the following is
![SOLVED:Find equations of the normal plane and osculating plane of the curve at the given point. x = \sin 2t , y = -\cos 2t , z = 4t ; (0, 1, 2 \pi) SOLVED:Find equations of the normal plane and osculating plane of the curve at the given point. x = \sin 2t , y = -\cos 2t , z = 4t ; (0, 1, 2 \pi)](https://cdn.numerade.com/previews/bf4f03af-d406-4279-8114-b9a64d3db761.gif)